0=3x^2-7x-286

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Solution for 0=3x^2-7x-286 equation:



0=3x^2-7x-286
We move all terms to the left:
0-(3x^2-7x-286)=0
We add all the numbers together, and all the variables
-(3x^2-7x-286)=0
We get rid of parentheses
-3x^2+7x+286=0
a = -3; b = 7; c = +286;
Δ = b2-4ac
Δ = 72-4·(-3)·286
Δ = 3481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3481}=59$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-59}{2*-3}=\frac{-66}{-6} =+11 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+59}{2*-3}=\frac{52}{-6} =-8+2/3 $

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